A: Luckily for you, fan Ryan Hackel asked himself this very question, and did the math to find out the answer! See his answer below:
In UberChrononauts, the universe is destroyed if, at any time, there are 13 paradoxes within any four consecutive rows of the timeline. (This is especially important to Crazy Joe, the Lost ID who wins by killing the universe.)
But, if your game table is like mine, it has a hard time holding all 64 timeline cards in the traditional 8×8 arrangement (69 with the Gore Years). More often than not, I have to arrange the timeline in a different configuration to make it fit conveniently, with 9, 10, or even 12 cards per row as the table size dictates.
But wait, if I change the number of rows, it also messes with the number of possible paradoxes in each row. If there are more or less than 8 cards per row, the magic number 13 for timeline collapse is no longer valid!
So, I’ve done the math. For timeline configurations between 6 and 14 cards per row, I counted the number of Ripplepoints per row (always with the Gore Years included). Then I summed up the number of Ripplepoints per every set of four consecutive rows, and took an average. Then I compared the average Ripplepoint density against that of the usual 8-per-row timeline, and scaled the magic 13 accordingly.
6 cards per row = 9 paradoxes within four rows
7 cards per row = 11 paradoxes within four rows
8 cards per row = 13 paradoxes within four rows
9 cards per row = 14 paradoxes within four rows
10 cards per row = 16 paradoxes within four rows
11 cards per row = 17 paradoxes within four rows
12 cards per row = 19 paradoxes within four rows
13 cards per row = 20 paradoxes within four rows
14 cards per row = 23 paradoxes within four rows
Note that the number of paradoxes is approximately 1.6x the number of cards per row, in case you need a quick rule of thumb.